# How many ways can 10 similar beads be arranged to form a necklace?

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Answer: This is called a cyclic permutation. The formula for this is simply (n-1)!/2, since all the beads are identical. Hence, the answer is 9!/2 = 362880/2 = 181440.

## How many necklaces can be made by using 10 round beads all of a different colors?

There are 10 beads of distinct colours; say, A, B, C, D, E, F, G, H, I and J. If no restriction is imposed then, there are (10!) = 3628800 ways to put these ten distinctly coloured beads into a necklace.

## How many ways can 5 different beads be arranged to form a necklace?

So, we have to divide 24 by 2. Therefore the total number of different ways of arranging 5 beads is 242=12 .

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2520. 5040.

## How many necklaces can be made using 7 beads of which 5 are identical red beads and 2 are identical blue beads?

= 720/(120*2) = 3. So we can have 3 different necklaces.

## How many necklaces can be formed with 6 white and 5 red beads if each necklace is unique how many can be formed?

5! but correct answer is 21.

## How many ways can you make a bracelet with 5 different beads?

Thus for n=5, there are possible 4!/2=12 different bracelets.

## How many different change can be made using 5 different Coloured beads?

So there can be 12 different arrangements.

## How many ways can we arrange 5 different colors in a circular arrangement?

Example 7.4.

We are looking for permutations for the letters HHHHTT. The answer is 6! 4! 2!

## How many necklaces of 12 beads each can be made from 18 beads of various Colours?

Correct Option: C

First, we can select 12 beads out of 18 beads in 18C12 ways. Now, these 12 beads can make a necklace in 11! / 2 ways as clockwise and anti-clockwise arrangements are same. So, required number of ways = [ 18C12 . 11! ] / 2!

## How many ways can 8 beads of different Colour be strung on a ring?

2520 Ways 8 beads of different colours be strung as a necklace if can be wear from both side.

## How many ways can a necklace be formed from 2 red and 2 blue beads?

= 1,680. Total of permutations = 2,520+3*1,680 = 7,560.